Here is the Calculation and research done .
Could You help me verify if everything is correct?

This would mean I could reduce the planet size to the Mars like size and preserving the similar gravity to Earth by altering a bit the Core composition of the metals and so the density and attraction.
This will allow me to reduce distances and consider to scale the map above to half and eventually halven it even more if I will consider it to be just a single side of the northern hemisphere.
reducing so the distances by 4 times.

Planet Data:
Planet Ausur
Volumes :
Radius 3400 Km
• Volume = (Vmantle ): 1,6455274666666666666666666666667e+20 m^3
• Volume of the Core (Vcore ): 2.9605×10^19 cubic meters
• Volume of the Mantle (Vmantle ): 1.325725××10^20 cubic meters
• Volume of the Crust (Vcrust ): 2.4675 ×10^18 cubic meters
Core Heavy Metals Proportions:
• Iron (Piron ): 75.6%
• Nickel (Pnickel ): 22.0%
• Other Heavy Materials (Pother ): 2.4%
Densities
• Crust Density (Dcrust ): Assumed to be Earth's crust density, 2,700 kg/m³
• Mantle Density (Dmantle ): Assumed to be Earth's mantle density, 3,300 kg/m³
• Dcore≈7,732.12kg/m³ Dcore=(Piron⋅Diron)+(Pnickel⋅Dnickel)+(Pother⋅Doth er)
o Iron Density (DironDiron): 7,870 kg/m³
o Nickel Density (DnickelDnickel): 8,910 kg/m³
o Other Heavy Materials Density (DotherDother): 10,000 kg/m³
Masses
Mcore= Miron+Mnickel+Mother = 7.37339×102^4 kg
Miron = Piron×Diron×Vcore = 1.4114×10^24 kg
Mnickel = Pnickel×Dnickel×Vcore = 4.1157×1023 kg
Mother =Pother×Dother×Vcore = 4.4805×1022 kg
Mmantle=Dmantle×Vmantle = 4.3796425×10^24 kg
Mcrust=Dcrust×Vcrust = 6.67025×10^21 kg
Mplanet=Mcore+Mmantle+Mcrust = 1.1123109×10^25 kg.

g=R2G⋅M
Where:
• gg is the gravitational acceleration (gravity) in meters per second squared (m/s²).
• GG is the gravitational constant, approximately equal to 6.67430×10−116.67430×10−11 N·m²/kg².
• MM is the mass of the planet in kilograms (kg).
• RR is the radius of the planet in meters (m).
This formula relates the gravitational acceleration (gg) to the mass (MM) and radius (RR) of the planet.
g=(6.67430×10^(−11) N·m²/kg²⋅1.1123109×10^25kg)/(3400⋅1000 m )^2
g≈9.259m/s²